I'm not a mathematician. It works like magic for me. Simply put. Suppose you have 64 bits (8 bytes) of regular RAM. For ECC-enabled memory, a similar block of

I'm not a mathematician. It works like magic for me. Simply put. Suppose you have 64 bits (8 bytes) of regular RAM. For ECC-enabled memory, a similar block of memory will occupy 72 bits (9 bytes). The first 64 bits will be identical. What would need to be stored in the remaining 8 bits so that any of the 72 bits could be detected and recovered, assuming only one bit was corrupted?