> Hillel says, "This isn't decomposable into two binary ops because you can't assign the range to a value and then step the value later." Well, maybe not (I don

> Hillel says, "This isn't decomposable into two binary ops because you can't assign the range to a value and then step the value later." Well, maybe not (I don't know Elixir), but it seems clear enough what r//2 should do if r is the name of a range value: it should produce a new range stepping either by 2 or by twice the previous step. This is exactly how `1 to 10 by 2` works in scala.