3 ms·
The output of the instruction is, for each 16-bit lane, the sum of two products of one i8 and one u8. 32640 * 2 > 32767 As an aside, the quoted section of the
by anonymoushn 2y ago
The output of the instruction is, for each 16-bit lane, the sum of two products of one i8 and one u8.
32640 * 2 > 32767
As an aside, the quoted section of the article seems to have an error. The maximum value of an i8 is 127 and the maximum value of one of these products is 32385.