3 ms·
"As the walker begins to move, she or he receives raindrops that would have fallen in front, while missing the drops that now fall behind. This creates a balanc
by knowitnone 2y ago
"As the walker begins to move, she or he receives raindrops that would have fallen in front, while missing the drops that now fall behind. This creates a balance, and ultimately, the amount of rain received on horizontal surfaces remains unchanged, regardless of the walking speed."
This is wrong. The back, stationary or moving forward does not receive rain. When stationary, the top receives rain(ideal model). When moving forward, the front AND the top receive rain. I don't see the balance they are claiming.
- deleted 2y ago[deleted]
- heisenzombie 2y agoThis is integrating over a distance, not a time. If you stay stationary you never get to your destination and get an infinite amount of rain (and the question is just ill posed). If you move with even a tiny forward velocity then you'll start getting a few raindrops on your front. As you go faster, you get more rain per second on your front but spend less time in the rain.
- photon_rancher 2y agoLikewise the minimum amount of rain you could catch would only be on your front from moving at an infinite speed. You’d leave behind a tunnel of missing raindrops in the shape of your profile along your path. As you move slower or faster you approach one limit or the other.