2 ms·
No, compilers don’t take endianness into account. (especially not C) You need to use a bit mask in order to make this code endian-independent rather than a poi
by odo1242 2y ago
No, compilers don’t take endianness into account. (especially not C)
You need to use a bit mask in order to make this code endian-independent rather than a pointer alias. Like (uint8_t)(int & 0xFF), or something like that.