3 ms·
Not really, i \in (0..dim).step_by(32), shift \in {0, 32}, but for `i % 32` it's 0..32
by urcyanide 2y ago
Not really, i \in (0..dim).step_by(32), shift \in {0, 32}, but for `i % 32` it's 0..32
- chrismorgan 2y agoSorry, I wrote `i % 32` by accident, I meant `i & 32`.