3 ms·
Having recently purchased a RTL-SDR and watched and learned about FM -- there is "pilot" frequency that doesn't change and is fixed relative to the tuner freque
by jasonjayr 2y ago
Having recently purchased a RTL-SDR and watched and learned about FM -- there is "pilot" frequency that doesn't change and is fixed relative to the tuner frequency. See this chart here:
https://en.wikipedia.org/wiki/FM_broadcasting#/media/File:RDS_vs_DirectBand_FM-spectrum2.svg https://en.wikipedia.org/wiki/FM_broadcasting#/media/File:RD...
Each radio station has 100khz of bandwidth centered on it's tuner frequency. in the, there are channel spacing rules that give some gaps +/- another 100khz of that. (That's why in the US, radio stations are typically on 'odd' decimals, ie 92.3 mhz, 94.1 mhz, etc) That chart does not show HD radio frequencies, which due to those spacing rules, and more accurate transmitters, are on the +/- 100khz spaces along side the original analog 100khz. You can "see" the audio modulating the frequency on the spectrogram. But the OFDM digital signal on either side looks like a band of more intense noise. It's mind blowing to realize there's a signal in that!
- lrasinen 2y agoThe pilot is there for stereo decoding, it has nothing to do with the ability to tune to an FM station. https://wiki.analog.com/university/courses/electronics/electronics_lab_fm_detectors https://wiki.analog.com/university/courses/electronics/elect... has some of the analog approaches collected.
- jasonjayr 2y agoYou're right -- after reading some of the peer responses, I realized that (I think...) my response is just how the Broadcast FM signal modulates the parts of the signal, and not how it actually 'locks on'. I'm still learning!
- lrasinen 2y agoI got an RTL-SDR this summer and brushed up my DSP skills playing with FM signals. PLLs are marvellous beasts; you can do a slapdash job in "designing" one and it'll still probably lock on just fine. Might not be optimal but will still lock. Another fun one, when you have IQ samples, is the polar discriminator: calculate x[t] * x*[t-1] where x* is the complex conjugate, and take the angle with arctan. Feels a bit like magic ("is that all?") but is justified by the theory.