4 ms·
I must say, this 'challenge' is a creative idea. However, not to be a wet blanket, but it's rather simple to construct a winning algorithm, particularly if you
by chimeracoder 14y ago
I must say, this 'challenge' is a creative idea.
However, not to be a wet blanket, but it's rather simple to construct a winning algorithm, particularly if you can both choose the same starting number and always go first (and choose the same starting number multiple times). If I had a few extra minutes at work right now, I'd take a stab at it.
...That is, unless that's the entire point?