2 ms·
That is not true with PACELC https://en.wikipedia.org/wiki/PACELC_theorem https://en.wikipedia.org/wiki/PACELC_theorem
by shepherdjerred 2y ago
That is not true with PACELC
https://en.wikipedia.org/wiki/PACELC_theorem https://en.wikipedia.org/wiki/PACELC_theorem
- shepherdjerred 2y agoTo clarify I’m not saying PACELC invalidates PAC, just that it expands to consider the case where there isn’t a partition.