3 ms·
With this logic (oft repeated) we should be sending TCP as JSON. { sourcePort: 443, destinationPort: 12345,...} Debugability is important but the answer is to
by anotherhue 2y ago
With this logic (oft repeated) we should be sending TCP as JSON. { sourcePort: 443, destinationPort: 12345,...}
Debugability is important but the answer is to build debugging tools, not to lobotomise the protocol for the vanishingly tiny fraction of packets that are ultimately subject to debugging.