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I'd flip your comment about optical surfaces: they need to be smooth, not continuous, and smoothness is actually not required either! The requirement is a consi
by itishappy 2y ago
I'd flip your comment about optical surfaces: they need to be smooth, not continuous, and smoothness is actually not required either! The requirement is a consistent phase relationship, which allows the signals to add together nicely via interference. Rays coming from same direction take the same path to the detector and interfere constructively, while rays coming from different directions tend to cancel.
For optical frequencies, the phase is difficult to measure directly, so we instead polish the surfaces down to a fraction of the wavelength of light (so that it all has the same phase). For radio telescope, the frequency is a lot lower, and we actually can measure the phase directly, so we can make our sensors crazy shapes and adjust it by adding delay. If you can change the individual delays (say, via software) you can change how they interfere and therefore change the sensitive direction for your telescope. This is how phased arrays function.
- netcraft 2y agosorry, yeah, thats a much better way of saying it and my smooth vs continuous was just confusing
- itishappy 2y agoYour comment was great! I'm not trying to correct you so much as adding additional context.
- ambicapter 2y agoWhy is it difficult to measure the phase directly for optical wavelength as opposed to radio? Is it purely because the shift is smaller?
- itishappy 2y agoIt's really fast. Visible frequencies are in the THz to PHz range, while radio frequencies are in the kHz. Modern electronics are fast enough to sample the latter but not the former.
- varjag 2y agoRadio frequencies are in KHz to THz range. There is equipment already operating in sub-THz bands but not yet close to the frequencies of light.