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> * P(correct) = (1-e)^n * This diverges exponentially I don't get it, 1-e is between 0 and 1, so (1-e)^n converge to zero. Also, a probability cannot diverg
by littlestymaar 2y ago
> * P(correct) = (1-e)^n
* This diverges exponentially
I don't get it, 1-e is between 0 and 1, so (1-e)^n converge to zero. Also, a probability cannot diverge since it's bounded by 1!
I think the argument is that 1 - e^n converges to 1, which is what the law is about.
- vbarrielle 2y agoP(correct) converges to zero, so you get almost certainly incorrect, at an exponential rate. The original choice of terms is not the most rigorous, but the reasoning is sound (under the assumption that e is a constant).
- hackerlight 2y agoP(correct) doesn't go down with token count if you have self-correction. It can actually go up with token count.
- littlestymaar 2y agoAh yes I didn't pay attention that it was the probability of being correct I misread it as the probability of being incorrect since the claim was that it diverged.