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I'm confused. Hawking temperature is inversely proportional to the mass. I assume most black holes except the very small ones would thus have a hawking tempera
by ithkuil 2y ago
I'm confused.
Hawking temperature is inversely proportional to the mass. I assume most black holes except the very small ones would thus have a hawking temperature lower than the CMB.
Does that mean that effectively no black holes will ever evaporate not even a tiny bit well until the future time when the CMB will be so red shifted that black holes will start to have net radiation?
- LegionMammal978 2y agoWikipedia suggests that this is the case [0]: "However, since the universe contains the cosmic microwave background radiation, in order for the black hole to dissipate, the black hole must have a temperature greater than that of the present-day blackbody radiation of the universe of 2.7 K. A study suggests that M must be less than 0.8% of the mass of the Earth – approximately the mass of the Moon." I'm not sure where the discrepancy between the mass of the Moon vs. an asteroid comes from, though. [0] https://en.wikipedia.org/wiki/Hawking_radiation#Black_hole_evaporation https://en.wikipedia.org/wiki/Hawking_radiation#Black_hole_e...
- mr_toad 2y agoThe CMB temperature is declining as the universe expands. When it was first created it was the temperature of incandescent plasma, and it shone like the Sun.