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>"Can a compass and straightedge construct a line segment of any length? By Gauss’s time, mathematicians knew the surprising answer to this question. A length
by peter_d_sherman 2y ago
>"Can a compass and straightedge construct a line segment of any length? By Gauss’s time, mathematicians knew the surprising answer to this question.
A length is constructible exactly when it can be expressed with the operations of addition, subtraction, multiplication, division or square roots applied to integers.
[...]
Remarkably, the rudimentary tools that the ancient Greeks used to draw their geometric diagrams perfectly match the natural operations of modern-day algebra: addition (+), subtraction (–), multiplication (x), division (/) and taking square roots (√).
The reason stems from the fact that the
equations for lines and circles only use these five operations
, a perspective that Euclid couldn’t have envisioned in the prealgebra age."
Related:
https://en.wikipedia.org/wiki/CORDIC https://en.wikipedia.org/wiki/CORDIC
- lainga 2y agoWhat privileges the square root over any other fractional power?
- xrisk 2y agoPresumably the hypotenuse of a right angled triangle.
- gilleain 2y agoIndeed. Related is the Ammann-Beenker tiling and it's connections to the 'Silver Ratio' of sqrt(2) + 1. * https://en.wikipedia.org/wiki/Silver_ratio https://en.wikipedia.org/wiki/Silver_ratio * https://en.wikipedia.org/wiki/Ammann%E2%80%93Beenker_tiling https://en.wikipedia.org/wiki/Ammann%E2%80%93Beenker_tiling
- hinkley 2y agoHypotenuse of a 1x2 unit right triangle, to be precise. By Pythagoras, the square root of any sum of squares can be drawn trivially with a compass and a straight edge. So 2, 5, 7, 10, 13, 17, etc
- xyzzyz 2y agoFinding intersection points of a circle with a line is equivalent to solving a system of equations, where one equation is that of a circle, (x-a)^2 + (y-b)^2 = r^2, and the second is that of a line, Ax + By = C. To solve it, you’ll be taking square roots, and not other roots. Similarly, to find intersection of two circles, you’ll be taking square roots, and not other roots.