2 ms·
I wonder if you're thinking of the efficiency penalty for dealing with big-endian values on a little-endian architecture. As the sister comment says, there's no
by foldr 2y ago
I wonder if you're thinking of the efficiency penalty for dealing with big-endian values on a little-endian architecture. As the sister comment says, there's nothing inherently more efficient about either byte order when it comes to the processor performing arithmetic operations in on values in its native byte order.