3 ms·
Odds for N tickets as odd(N): odd(0) = 0 odd(1) = X, so odd(1) / odd(0) = +Inf increase in odds of winning vs 0 odd(2) = 2X, so odd(2) / odd(1) = 2x increase
by web007 2y ago
Odds for N tickets as odd(N):
odd(0) = 0
odd(1) = X, so odd(1) / odd(0) = +Inf increase in odds of winning vs 0
odd(2) = 2X, so odd(2) / odd(1) = 2x increase in odds of winning vs 1