5 ms·

Initial Litium deactivation is 30 % compared to 9 % with slow formation loading.

• lightedman 2y ago
  How much capacity is lost as a result of this?
  • soulofmischief 2y ago
    Lithium deactivation is inversely proportional to capacity. We could just add extra capacity to make up for it, though. From there, the battery would maintain capacity for a longer time than before.
    • westurner 2y ago
      Isn't there how much fire risk from charging a _ battery at higher than spec currents?
      • imp0cat 2y ago
        It's just the single inital charging that has to be at high current.
        • westurner 2y ago
          So for SAFETY then there also shouldn't there be battery fire containment [vessels] for the production manufacturing process?
          • imp0cat 2y ago
            Absolutely, but I hope there already are measures taken to prevent and contain battery fires during manufacturing.
    • metaphor 2y ago
      > We could just add extra capacity to make up for it, though. At naive face value, "just" adding an extra 30% capacity to offset expected lithium deactivation implies proportional increases in material COGS and package mass/volume, all other factors being equal. Unless (a) a manufacturer is optimizing for throughput; (b) production is constrained at this initial charge stage; and (c) supply substantially lags demand; this strikes me as a non-starter in most of the consumer space.
      • soulofmischief 2y ago
        Extra 21% capacity. Current practice still burns 9%. Lithium batteries have become very cheap, and I would pay a markup for a 50% longer battery life, assuming it didn't (a) further normalize non-replaceable batteries in consumer electronics or (b) lead to even worse conditions for the quasi-slaves currently mining lithium. Unfortunately, I doubt either of those will hold.
        • metaphor 2y ago
          > Extra 21% capacity. Current practice still burns 9%. On a normalized basis, if current practice yields 91% finished capacity (i.e. 9% deactivation loss), and the new proposed process is expected to yield 70% finished capacity (i.e. 30% deactivation loss), then the question is how much initial material must the new proposed process start with to end with the equivalent finished capacity as the current practice? FinCap = InitCap * (1 - DeactivationRate) 0.91 0.91 = InitCap * 0.70 --> InitCap = ---- = 1.30 0.70
          • soulofmischief 2y ago
            Good point, I didn't think that through. Thanks for the correction.