4 ms·
For old-school software developers 4*8 is easy because both numbers are powers of 2. I compute expressions like that as 2 ^ ( log2(4) + log2(8) ) = 2^(2+3) = 2^
by Const-me 2y ago
For old-school software developers 4*8 is easy because both numbers are powers of 2. I compute expressions like that as 2 ^ ( log2(4) + log2(8) ) = 2^(2+3) = 2^5