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Isn't giving the caller control over the memory exactly what this API does? The caller just passes in a block of memory that will be used for all of the interna
by connicpu 2y ago
Isn't giving the caller control over the memory exactly what this API does? The caller just passes in a block of memory that will be used for all of the internal allocations as well as the strings returned by the API.
- WalterBright 2y agoIf I misunderstood it, then you are correct.