41 ms·
Well, it could be for example that /proc is not mounted. A lot of software breaks for this, while really there is no need for it to be so. Also that approach on
by alerighi 2y ago
Well, it could be for example that /proc is not mounted. A lot of software breaks for this, while really there is no need for it to be so. Also that approach only works on Linux, if you want to write a portable software what you do?
- mbrumlow 2y agoI am mainly pointing out that arg[0] is still valid. Writing portable software is an entirely different topic.