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That's not sufficient to be unsurprising. What if a sum has more than 2 consecutive Fibonacci numbers? That doesn't cause a problem, but it takes a little more
by lupire 2y ago
That's not sufficient to be unsurprising.
What if a sum has more than 2 consecutive Fibonacci numbers? That doesn't cause a problem, but it takes a little more work to sort it out.
- muti 2y agoI find the distinct property much more interesting and non obvious. It looks like non consecutivity is only there to force unique solutions hence called zeckendorf representations