3 ms·
The article shows: fn(n miles to km) ≅ next_fib(n) fn(n km to miles) ≅ prev_fib(n) --- Similarly, fn(n kg to lbs) ≅ prev_fib(n) + next_fib(n) fn(n lbs to
by OutOfHere 2y ago
The article shows:
fn(n miles to km) ≅ next_fib(n)
fn(n km to miles) ≅ prev_fib(n)
---
Similarly,
fn(n kg to lbs) ≅ prev_fib(n) + next_fib(n)
fn(n lbs to kg) ≅ (prev_fib(n) - prev_fib(prev_fib(n))) * 2
fn(fib(i) lbs to kg) ≅ fib(i-1) - fib(i-4) # Alternate formula
- madcaptenor 2y agoThis is basically multiplying by sqrt(5) ~ 2.236, and 1 kg = 2.204 lb. Not bad!