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Before I finish typing this, I want to make it clear that I'm just having fun with the numbers/math/language here. Even that statement doesn't really work outs
by taeric 2y ago
Before I finish typing this, I want to make it clear that I'm just having fun with the numbers/math/language here.
Even that statement doesn't really work outside of fully unique values across a specific distribution. Take samples where you have many duplicates, and you can easily have the vast majority of values flat out be the average/median when you have some distributions. Is why I picked average number of fingers. The VAST majority of counts there are the same value. The outliers being dwarfed to insignificance both high and low.
For more continuous distributions, https://stats.stackexchange.com/questions/326304/in-a-given-set-of-numbers-can-there-be-more-than-half-above-mean-median-or-mode https://stats.stackexchange.com/questions/326304/in-a-given-... is a pretty good quick google of what I mean.
Now, what is the distribution of driving ability? I have no idea. I see no reason to think it is a normal distribution, though.