4 ms·
Most unfortunately, it was proven that the digits are periodic. Its a complex formula, but they are periodic, where as the digits of sqrt (2) are algebraic, and
by ForOldHack 2y ago
Most unfortunately, it was proven that the digits are periodic. Its a complex formula, but they are periodic, where as the digits of sqrt (2) are algebraic, and the digits of e are logarithmic. So without using the identity elements of the arithmetic group, you simply arrive at three very different classes of irrationality.