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It's statically ensured, the same way I can trust if you generate a Bitcoin address right now it won't have a few thousand bitcoins in it.
by patmcc 2y ago
It's statically ensured, the same way I can trust if you generate a Bitcoin address right now it won't have a few thousand bitcoins in it.
- shawnz 2y agoNo, it's not like that: generate a random Bitcoin address and it's practically guaranteed that it will be empty. But in this case, if the time traveler picks a random key for their secret, it's equally likely that it gets brute forced on the first attempt as it is the trillionth attempt. There's no statistical guarantee except that on average it will take a certain number of attempts.
- deleted 2y ago[deleted]
- geor9e 2y agoStatistically? With that analogy, you'd design a crypto algorithm that, on average, gets cracked on the desired date to guess the wallet with a few thousand bitcoins. You still have the problem that (1) guessing it right on that desired date, (2) guessing it right today, and (3) guessing it right on a day 42 times the amount of time as the desired date, all have exactly equal probability. You don't get to pick from infinite timelines to make your plot work, you get 1 try, and need to be somewhat sure it'll work on that date. It might not be possible. Unless you time travel and just hand them the information.
- Workaccount2 2y agoSure but the compute difference between decades isn't as dramatic as decrypting vs not decrypting Bitcoin.