3 ms·
It doesn't make sense from a strict type and set theory point of view because it doesn't make sense from a strict type and set theory point of view. Neither C n
by formerly_proven 2y ago
It doesn't make sense from a strict type and set theory point of view because it doesn't make sense from a strict type and set theory point of view. Neither C nor C++ are rigorous languages.
We also have "void foo(void)" and here void takes on two entirely different meanings, while type theory would suggest this is a function that diverges if it were called, which you can't.