4 ms·
For what it's worth, Haskell's Integer type is that way. edit To be clear, in Haskell you 'default' to using its arbitrary-precision type, unlike say Java wher
by MaxBarraclough 2y ago
For what it's worth, Haskell's Integer type is that way.
edit To be clear, in Haskell you 'default' to using its arbitrary-precision type, unlike say Java where they're available in the standard library but not in the core primitive types.