3 ms·
> This new pi value should land us on the precise nanometer on a planetary rock of a sun located about 18 trillion light years away. 40 digits or so will get y
by slyall 2y ago
> This new pi value should land us on the precise nanometer on a planetary rock of a sun located about 18 trillion light years away.
40 digits or so will get you that...
- hughesjj 2y agoNah, observable universe is only 93B light years in "diameter" at the current "moment"
- theandrewbailey 2y ago93 billion light years is 8.798×10^26 meters[0], so about 35 digits ought to suffice for any given nanometer. [0] https://www.wolframalpha.com/input?i=93+billion+light+years+in+meters https://www.wolframalpha.com/input?i=93+billion+light+years+...
- egberts1 2y agoNow that's a solid win for us math nerds.
- constantcrying 2y agoIn floating point arithmetic two consecutive operations can have an unbounded error. Just because the precision is good enough for one computation doesn't mean it is good enough for all computations.
- egberts1 2y agoVery good. Here's the WolframAlpha equation to your assertion of 40-digit ... or so. https://www.wolframalpha.com/input?i=%28180+x+17+trillion+light+years%29%2F%28pi+x1nm%29 https://www.wolframalpha.com/input?i=%28180+x+17+trillion+li...
- SushiHippie 2y agoPardon my ignorance, but what does this calculate?
- egberts1 2y agoCentral angle, of which you can use that exponential power to determine how many digits of π to minimize error tolerance. Also, I err'd. I swapped L and R. https://www.wolframalpha.com/input?i=%28180+x+1+nanometer%29%2F%28pi+x+17+trillion+ly%29 https://www.wolframalpha.com/input?i=%28180+x+1+nanometer%29...