3 ms·
It dereferences a mutable reference to h twice, ignoring its type with _s. I suppose this implies that h is a reference type itself.
by evrimoztamur 2y ago
It dereferences a mutable reference to h twice, ignoring its type with _s. I suppose this implies that h is a reference type itself.
- muricula 2y agoNo dereferences, just casts. It shouldn't generate any loads/reads from memory.