3 ms·

I find this strange: &mut h as *mut _ as *mut _ What is going on here?

• evrimoztamur 2y ago
  It dereferences a mutable reference to h twice, ignoring its type with _s. I suppose this implies that h is a reference type itself.
  • muricula 2y ago
    No dereferences, just casts. It shouldn't generate any loads/reads from memory.
• mkeeter 2y ago
  It's doing the following cast: &mut DeviceHandle -> *mut DeviceHandle -> *mut c_void (with the pointer types being solved for automatically by the compiler)
• dwattttt 2y ago
  It's a bit of a song and dance; you can turn a &mut T into a *mut T, and you can cast a *mut T into a *mut anything, but you can't do it in one step.