4 ms·
Until the strong exponential hypothesis is (dis-)proven, the quadratic cost is required or you have to give something up. Just the cost of exhaustive search.
by nyrikki 2y ago
Until the strong exponential hypothesis is (dis-)proven, the quadratic cost is required or you have to give something up. Just the cost of exhaustive search.
As (dis-)proving SETH will resolve the P vs NP problem, I wouldn't hold my breath.
The question is if a particular use case can accept those costs.
- MacsHeadroom 2y agoWhat makes you think that the thing you have to give up is related to model quality?