3 ms·
> Because clockspeed ramps power exponentially It's not exponential; P = C V^2 f, so power is something between O(f) and O(f^3), depending on how voltage scali
by oasisaimlessly 2y ago
> Because clockspeed ramps power exponentially
It's not exponential; P = C V^2 f, so power is something between O(f) and O(f^3), depending on how voltage scaling works. It follows that efficiency (energy per instruction) is something between O(1) and O(f^2).