3 ms·
Even Newton knew that party trick. The centrifugal force has to at least equal gravity when the glass is upside down, so F/m=w^2r=g. If r (the distance from the
by Y_Y 2y ago
Even Newton knew that party trick. The centrifugal force has to at least equal gravity when the glass is upside down, so F/m=w^2r=g. If r (the distance from the axis of revolution is about a metre, then w (the angular velocity) is roughly sqrt(10)/second. In more familiar terms that's about 30 rpm. Anything rotating that fast will be able to keep all its water in the glass.
- wumms 2y agoThanks! It seems to be possible: some roll rates I found (not very good sources, though): F/A-18E Super Hornet 120 deg/s [0], F-16 240 deg/s [0], Eurofighter 250 deg/s [0]. For the Starfighter I found up to 720 deg/s in some discussions, though I go with 360 deg/s [1]. Min. distance (r) from the glass of water to the roll axis to achieve 1g: 120 deg/s (20rpm): 245cm (you'd have to put that glass on the landing gear) 180 deg/s (30rpm): 100cm 240 deg/s (40rpm): 55cm 250 deg/s (42rpm): 51cm 360 deg/s (60rpm): 25cm 720 deg/s (120rpm): 6cm [0] https://theaviationist.com/2015/05/01/aileron-roll-in-t-346a/ https://theaviationist.com/2015/05/01/aileron-roll-in-t-346a... [1] https://www.key.aero/forum/modern-military-aviation/106866-roll-rate-data-of-jets https://www.key.aero/forum/modern-military-aviation/106866-r...