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I don't think so. It's a pretty uninteresting property of a function whether or not a particular person happens to know its value for a given input. It does not

by foldr 2y ago

I don't think so. It's a pretty uninteresting property of a function whether or not a particular person happens to know its value for a given input. It does not entail that the function is not computable, if that's what you're suggesting.