3 ms·
b^x = (e^ln(b))^x = e^( ln(b) * x ), and its derivative then is (by the chain rule) ln(b) exp( ln(b) * x ) = ln(b) * b^x.
by FabHK 2y ago
b^x = (e^ln(b))^x = e^( ln(b) * x ),
and its derivative then is (by the chain rule)
ln(b) exp( ln(b) * x ) = ln(b) * b^x.