The math for RSA is dead simple. But the theoretical foundations are not well established, no. It should be said though that SHA2 and AES also have unproven fou

The math for RSA is dead simple. But the theoretical foundations are not well established, no. It should be said though that SHA2 and AES also have unproven foundations for their security model. In a very strict sense both RSA and AES are equally vulnerable. But I think people would be more surprised if AES was catastrophically broken, and most surprised if SHA2 were, though there is little more than mathematical intuition underlying this.