By the same principle, these are exactly the same: arr[i][j] j[i[arr]] These are the simplifications you'd do. You only need to know that a[x][y] is equiv

By the same principle, these are exactly the same: arr[i][j] j[i[arr]] These are the simplifications you'd do. You only need to know that a[x][y] is equivalent to (a[x])[y], and that a[x] is the same as x[a]. arr[i][j] (arr[i])[j] (i[arr])[j] j[i[arr]]