5 ms·
Why would you assume that? Persumably there should be no real reason why HASH(8_char_password) = 160_bit_hash should be less strong than HASH(160_bit_hash). N
by yuvadam 14y ago
Why would you assume that?
Persumably there should be no real reason why HASH(8_char_password) = 160_bit_hash should be less strong than HASH(160_bit_hash).
Not only that, but most hashing algorithms already do several iterations before returning the hash.