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It also has no good definition for its semantics when presented with a NaN.
by pklausler 2y ago
It also has no good definition for its semantics when presented with a NaN.
- sagarm 2y agoYou would use a partial ordering: https://en.cppreference.com/w/cpp/utility/compare/partial_ordering https://en.cppreference.com/w/cpp/utility/compare/partial_or...
- pklausler 2y agoHow would that apply to Fortran’s arithmetic IF statement? It goes to one label for a negative value, or to a second label for a zero, or to a third label for positive. A NaN is in none of these categories.