3 ms·

To be clear, the construction given here violates the finite additivity property of measure. It's got nothing to do with the countable/uncountable additivity pr

To be clear, the construction given here violates the finite additivity property of measure. It's got nothing to do with the countable/uncountable additivity property.

emblaegh 2y ago
Yeah but this is only possible if the sets in question are uncountably infinite.
- adroniser 2y ago
  Yes but you are not taking an uncountable union. You are taking a finite union.