3 ms·
Physicists find a new way to represent 'pi'
- turtleyacht 2y agoLike with the three-body problem [1], would be interesting to apply statistics to "seemingly random perturbations." Maybe in this case the drunkard's walk is exclamatory announcements of the next digit of pi. Wrong so often, is there a measurement for that? One in ten choosing a unique digit per round would always be right, but is there a frequency to who is right more often? Maybe it averages to everyone being correct versus incorrect about the same number of times. [1] https://news.ycombinator.com/item?id=40758294 https://news.ycombinator.com/item?id=40758294
- gus_massa 2y agoThe article is very confusing. My takeaway after reading the paper for 15 minutes: (fixes and sugestions are wellcome) They are not calculation pi, but pi^2/6 = (2) = 1/1^2 + 1/2^2 + 1/3^2 + 1/4^2 + ... https://en.wikipedia.org/wiki/Riemann_zeta_function https://en.wikipedia.org/wiki/Riemann_zeta_function The problem is that when you add 1/n^2 you need a lot of terms to get high precition, like a few millons to get the 15 digits of a float. They rewrote the sum as another infinite sum, and with the new sum you can cut it just after 40 terms to get 15 digits precition. I think they rewrote a more general form. Calculatinnf pi (or pi^2) again is not very useful, but the new formula may be useful in expressions that use infinite sums similar to 1/n^2.