3 ms·
What none of the answers seem to touch on is the simplest case that would be a solution 99% of the time: If a previously connected to network (i.e. one we have
by ghusto 2y ago
What none of the answers seem to touch on is the simplest case that would be a solution 99% of the time: If a previously connected to network (i.e. one we have a key for) has more bars (which I as a user can see in the UI), that is the one that will work better.
Since this is almost always true, the technicalities of _actual_ strength don’t come into it, right?