3 ms·
It wasn't `x % 16` it was `x % y` where x and y are 16-bit integers. A compiler would also have taken care of it if it were just a literal.
by ladberg 2y ago
It wasn't `x % 16` it was `x % y` where x and y are 16-bit integers. A compiler would also have taken care of it if it were just a literal.
- drewg123 2y agoWhoops.. I misread what he was doing.