3 ms·
> [1] since e^x = 1 + x is generally true, why'd you even need a second order derivative Only true for small x (less than 1).
by glitchc 2y ago
> [1] since e^x = 1 + x is generally true, why'd you even need a second order derivative
Only true for small x (less than 1).
- marginalia_nu 2y agoThe joke is that physicists aren't always rigorous enough to add that caveat.