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I know about the hydrodynamic analogues, and I've seen the double-slit experiment with the bouncing droplet. However, it is unfortunately not a very good model,
by simiones 2y ago
I know about the hydrodynamic analogues, and I've seen the double-slit experiment with the bouncing droplet. However, it is unfortunately not a very good model, as it requires changes in the wave to propagate at infinite speed in order to explain other experiments (the ones that fail Bell's inequalities). And that in turn causes many other problems as well. Not to mention, the pilot wave interpretation actually needs lots of work that no one has done yet to actually concur with QFT and the extraordinarily precise experiments that have confirmed the results there. So, it's a particularly problematic interpretation of quantum mechanics, despite having the neat hydrodynamic model.
- oneshtein 2y agoHydrodynamic model is not an interpretation or a theory - it's a model. Models are not perfect, but they are physical, they are real things in the real world, no need to prove anything, because they are the proof. HQM exists, it demonstrates quantum behavior, it has the pilot wave. If QFT doesn't fit the real world, then it is bad for theory, not for the real world.
- simiones 2y agoThe hydrodynamic analogue of quantum mechanics has some behaviors of QM, but not all. It's a nice analogy, and it is a real physical system of course, but it is not how elementary particles behave. If you construct a hydrodynamic experiment where two droplets are bounced on the same wave in different directions (analogous to two entangled particles moving in different directions), and then performed simultaneous measurements on them far away from each other, you would not see the same correlations between the measurements on the separate droplets that you see when doing this experiment with entangled particles. However, if you perform your measurement on one side, and after enough time on the other, you would see the expected correlation: the measurement on droplet A modifies the pilot wave, and that modification is carried over to affect the behavior of droplet B after some time. In experiments on elementary particles though, this time is 0, or at least much less than distance/c, which is why we say that QM pilot wave theory is non-local.
- oneshtein 2y ago> If you construct a hydrodynamic experiment where two droplets are bounced on the same wave in different directions (analogous to two entangled particles moving in different directions), and then performed simultaneous measurements on them far away from each other, you would not see the same correlations between the measurements on the separate droplets that you see when doing this experiment with entangled particles Why not? And what "measurement" means for walking droplets, when we can see the whole situation just by looking at it?
- simiones 2y agoMeasurement means the same thing in classical and quantum mechanics: you interact with the system using a measurement apparatus. For the particular experiment I'm thinking of, you'd have to interact with the bouncing droplets to measure some property that is shared by both through their common pilot wave. Most likely this should be something like adding a wave filter and seeing if the droplet is dissolved or not, similar to a polarization filter for light. The key is to perform the two measurements in a way that should show some correlation, such as checking for polarization under non-orthogonal angles. The reason why I'm certain that this experiment will not reproduce the quantum effect, even though I didn't perform it, is that classical wave polarization is a local phenomenon, it propagates at the speed of light (or much slower) from the location where the polarizer is added. Conversely, the kinds of correlations that have been observed between entangled particles are non-local: they can't be explained by the two particles exchanging information at speeds lower or equal to the speed of light. This is well established in experiments related to Bell's inequality. It is also well established in experiments that this doesn't hold true for classical systems.