4 ms·
You're too fixated on the example. It's obviously used in cases where you cannot group like that: (-b ± sqrt(b² - 4ac)) / 2a = 2c / (-b ∓ sqrt(b² - 4ac))
by stabbles 2y ago
You're too fixated on the example. It's obviously used in cases where you cannot group like that:
(-b ± sqrt(b² - 4ac)) / 2a = 2c / (-b ∓ sqrt(b² - 4ac))