3 ms·
What you’ve suggested is not equivalent. The a is always taken without negation, and that’s not the case in your rendering.
by billyjmc 2y ago
What you’ve suggested is not equivalent. The a is always taken without negation, and that’s not the case in your rendering.
- LordDragonfang 2y agoAh. "a±(b-c)" then. The fact I made that mistake in the first place just makes me more convinced the original form is unnecessarily complex to parse.
- stabbles 2y agoYou're too fixated on the example. It's obviously used in cases where you cannot group like that: (-b ± sqrt(b² - 4ac)) / 2a = 2c / (-b ∓ sqrt(b² - 4ac))