4 ms·
That's very computationally inefficient.
by DEADMINCE 2y ago
That's very computationally inefficient.
- aforwardslash 2y agoYou can trivially maintain a list of the size of the whole ipv4 space by using bitmaps
- TacticalCoder 2y ago> That's very computationally inefficient. It's O(1) with iptables/nftables ipsets. Moreover as I blocklist entire CIDR blocks, there aren't that many entries in those ipsets.