2 ms·
CROSS POST: I posted this in reply to your linked explanation. Okay yep I get it now. The 4mv2 did it for me mathematically but I still couldn't get it intuiti
by dools 2y ago
CROSS POST: I posted this in reply to your linked explanation.
Okay yep I get it now. The 4mv2 did it for me mathematically but I still couldn't get it intuitively until I imagined a car going 50mph rear ending a car going 40mph. If they wind up going the same speed as a result of the collision then the deceleration felt by the car in the back would only be 10mph if the car in front didn't change speed because it was like, an ocean liner. If the cars are the same size and the collision is perfect and all that then the car in front would gain 5mph and the car behind would lose 5mph.
Since in a head on, they are both changing speed then the deceleration must be half the combined relative deceleration.
The way I was imagining it was as if the car collides with another car going 50mph in a head on collision and the other car doesn't slow down due to the collision.
So it appears that it is I who am confidently wrong about physics (although I still hold that Milton Friedman is confidently wrong about economics!).