3 ms·
I have no idea how to calculate it, but I interpreted this to mean not that the earth rotated (which everyone is trying to calculate) but that the earth was cro
by Cerium 2y ago
I have no idea how to calculate it, but I interpreted this to mean not that the earth rotated (which everyone is trying to calculate) but that the earth was crossing the horizon of the moon such that four miles of earth crosses the horizon during the shot causing earth blur for a moon-stable reference frame.
- Thorrez 2y agoRevolved I think would be the correct term for that.
- mrb 2y agoFrom the moon's reference, the Earth orbits around it, traveling 2 × π × distance_moon_earth per orbit. Divide this by 27.3 days (sidereal orbital period) to get the Earth's speed. Multiply by 1/250th of a second. And we find this is, again, much less than 4 miles. Using GNU units: $ units "2 * pi * moondist / (27.3 day) * (second / 250)" Definition: 4.0958765 m which is only 0.0025450597 miles.